Cpp 3: Precedence & Associativity - Question 1

1. Question 1: x = 3 + 4 + 5

Task:

• Given a set of expressions that have no parentheses.
  
• Using the operator precedence and associativity rules:
  • add parentheses to each expression
  • to make it clear how the compiler will evaluate the expression.

Reference:

• https://en.cppreference.com/w/cpp/language/operator_precedence.html

2. Tp Solution

2.1 Operator: Precedence Level & Associativity

Operator ‘\(+\)’:

• Precedence: \([3]\)
• Associativity: \([L \to R]\)

Operator ‘\(=\)’:

• Precedence: \([16]\)
• Associativity: \([L \leftarrow R]\)

2.2 Workout

\[x = 3 + 4 + 5;\] \[x_{16} = {}_{16}3_{3} + {}_{3}4_{3} + {3}_5\] \[x_{16} = {}_{16}(3_{3} + {}_{3}4)_{3} + {3}_5\] \[x_{16} = {}_{16}(3+4)_{3} + {}_{3}5\] \[x_{16} = {}_{16}((3+4)_{3} + {}_{3}5)\] \[x_{16} = {}_{16}((3+4)+5)\] \[x_{16} = {}_{16}((3+4)+5)\] \[(x=((3+4)+5))\]